If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
((b^0)/12)*a^2 = 0
(1/12)*a^2 = 0
1/12*a^2 = 0
x należy do R
x in (-oo:+oo)
| 12=-12+m | | X^2+5x=4x+12 | | x^2-32x+c= | | 3x+(-2x-18)=-75 | | 6(2a+b)= | | 14x+9=7x+41 | | 0.8(0.1-2x)=-1.3x | | 45m-25=16 | | 6z+2=7z | | 10x-12=24 | | sqrt(3a/2)-1=5 | | 3y+7=z+9 | | 18(y-97)=y-9 | | .5(5-7x)=8-(4-6x) | | x=0.5-3(0.33) | | .14x+9=7x+41 | | x=3(7/11) | | 3z+7=z+9 | | x=.5-3(.33) | | 18(y-97)=y+(-9) | | 1+w=8 | | 3n-15=2n+3 | | x=0+.75(.33) | | 3(7/11)=x | | 3y+5=x | | n/-3=12 | | 21=-9+b | | -2p-3-p=18 | | v^2+v-2= | | ×/6=8 | | y=7.5(3)+4 | | 7(7c+1)=13(3c-2) |